Problem G: 函数参数的传递

请选择以下(1)~(12)处的输出。

#include <bits/stdc++.h>
using namespace std;

int square0(int n)
{
    cout << "address of n0 in square0(): " << &n << "\n";
    n *= n;
    return n;
}

void square1(int* n)
{
    cout << "address of n1 in square1(): " << n << "\n";
    *n *= *n;
}

void square2(int& n)
{
    cout << "address of n2 in square2(): " << &n << "\n";
    n *= n;
}

int main()
{
    int n[3];
    n[0] = 8;
    cout << "address of n0 in main(): " << &n[0] << "\n";
    cout << "Square of n0: " << square0(n[0]) << "\n";
    cout << "After execute square0() in n0: " << n[0] << "\n";

    n[1] = 8;
    cout << "address of n1 in main(): " << &n[1] << "\n";
    square1(&n[1]);
    cout << "Square of n1: " << n[1] << "\n";
    cout << "After execute square1() in n1: " << n[1] << "\n";

    n[2] = 8;
    cout << "address of n2 in main(): " << &n[2] << "\n";
    square2(n[2]);
    cout << "Square of n2: " << n[2] << "\n";
    cout << "After execute square2() in n2: " << n[2] << "\n";

    return 0;
}

address of n0 in main(): （1）

address of n0 in square0(): （2）

Square of n0: （3）

After execute square0() in n0: （4）

address of n1 in main(): （5）

address of n1 in square1(): （6）

Square of n1: （7）

After execute square1() in n1: （8）

address of n2 in main(): （9）

address of n2 in square2(): （10）

Square of n2: （11）

After execute square2() in n2: （12）